Thursday, 12 February 2015
Sunday, 8 February 2015
Ans C
now int, char and double are basically datatypes in C language.lets understand what each of them mean
A] Int is used to define integers.
int i;
i = 5;
here i is defined as integer (basically it is a memory location allocated to store integer value) and assigned a value 5.
B] char is used to define character.
char let ;
let = 'x';
C] double use to define floating point numbers (e.g = 5.46 , 6.81)
double j ;
j = 4.5;
Now consider above question we have,
int i = 3;
int j = 7;
double f = 5.5 ;
double g = 4.5;
char ch = 'T' ;
- || means OR
- && means AND
- == means Equal to
Consider option A
(i < = 5 ) && ( ch == 'T')
for above eq. to give true value both expression should be true lets check them.
as i =3 it is less than 5 so first expression is indeed true.
now ch = 'T' is also given in question so it is also true as both expressions are true above equation will give vale TRUE.
Consider option B
(i < 8 ) || ( ch = ' L')
for above eq. to give true value one expression should be atleast true lets check them.
as i =3 it is less than 8 so first expression is indeed true.
so above equation gives TRUE value.
Consider option C
(f > 6) || (i*j < 15)
as f = 5.5 first expression is false
i* j = 16.5 which is greater than 15 so this expression is also false.
so the value of equation is FALSE
So option C is correct option.
Ans . B
A] Current density (J ) is given by
J = p* Vd ----------------------- (1)
where,p = charge density
Vd = drift velocity
B] Charge density is basically no. of charges present inside the material so it is given by.
p = n* q ---------------------------------(2)
where,
n = no. of charge carrier (say electron in our case)
q = charge carried by charge carrier.
C] Drift Velocity is given by
Vd = u*E -------------------------------(3)
where,
u = Mobility
E = Electric field.
So J becomes,
J = n*q*u*E -------------------(4)
D] Ohm's law according to classical electromagnetic theory is given by,
J = k*E -------------------------------(5)
where,
k = conductivity
E = Electric field.
Equating 4 and 5 we have
k = n* q* u
for above question
n = Nd as it is n-type semiconductor.
q = charge on electron = 1.6E-16
u = 1350
substituting in equation (6) we get,
k = 9.2592 E+14
so answer is B
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